capacitive current calculator
Compute capacitor current using 𝐼=2𝜋𝑓𝐶𝑉 or I= v/𝑋C where Xc=1/2rfc.Supports RMS/peak, 50/60 Hz, and any capacitance.
reactive current calculator
Capacitive current increases as a function of frequency and capacitance and and is 90 degrees leading in phase with voltage. Apply RMS formulae to sine waves or i(t)=C(dv/dt) to transients. Current through a capacitor in AC is stipulated by frequency, capacitance, and applied voltage.
Formula & Table Summary:
\( I_{\text{rms}} = 2\pi f C V_{\text{rms}} \)
\( X_C = \frac{1}{2\pi f C}, \ I_{\text{rms}} = \frac{V_{\text{rms}}}{X_C} \)
\( I_{\text{peak}} = \omega C V_{\text{peak}}, \ \omega = 2\pi f \)
60hz capacitor current
Compute current in capacitor by using voltage, frequency and capacitance. In sinusoidal AC, I = 2pi f C V, or equivalently, I = V/XC, with XC = 1/( 2pi f C).This kind of accurate calculation helps avoid over-heating, nuisance open-circuit, and component breakdown and ensures adherence to current ratings of switches, fuses and PCB traces.
capacitive reactance current
| Vrms (V) | f (Hz) | C (µF) | Calculation | Irms (A) |
|---|---|---|---|---|
| 230 | 50 | 50 | 2π·50·50e-6·230 | 3.61 |
| 120 | 60 | 20 | 2π·60·20e-6·120 | 0.905 |
| 240 | 60 | 100 | 2π·60·100e-6·240 | 9.05 |
| 110 | 50 | 10 | 2π·50·10e-6·110 | 0.346 |
| 400 | 50 | 200 | 2π·50·200e-6·400 | 25.13 |
Frequently Asked Questions - capacitive current calculator:
How do I calculate capacitor current?
Use I=2πfCVrms for sinusoidal AC, or I=Vrms/Xc with Xc=1/(2πfC).
Does current lead or lag in a capacitor?
Current leads voltage by 90° in a purely capacitive circuit.
What units should I use?
C in farads, f in hertz, V in volts, current in amperes.
How do I handle peak values?
Use Ipeak=ωCVpeak with ω=2πf.
What if the waveform isn’t sinusoidal?
Use i(t)=C dv/dt or do a frequency-domain analysis with harmonics.
How does frequency affect current?
Higher frequency lowers Xc and increases current linearly with f.
How does capacitance affect current?
Current is proportional to C; doubling C doubles current.
Can I use DC values?
For steady DC, current is zero after the transient; use i=C dv/dt during changes.
Is ESR important?
Yes, ESR adds resistive heating and limits allowable ripple current.
How to reduce capacitive current?
Lower the voltage or frequency, or reduce capacitance.
