energy charge voltage calculator
Convert energy and charge to voltage (and vice versa). Use V=E/Q or 2E/C for capacitors: handy for electronics and physics problems.

voltage from energy and charge
Use V = E / Q to discover voltage by knowing energy & charge. Long-term capability: to charge capacitors with stored energy. V = (x/2E/C). Deliver energy (J), charge (C), or capacitance (F) to be converted immediately.
Formula & Table Summary:
- \( V = \dfrac{E}{Q} \)
- \( E = QV \)
- \( E = \tfrac{1}{2} C V^{2} \Rightarrow V = \sqrt{\dfrac{2E}{C}} \)
- \( Q = C V \)
Units: E (J), Q (C), C (F), V (V). Convert prefixed units to base units first (mJ→J, µF→F).
coulombs to volts
EnergyChargeVoltage Calculator is a conversion tool relating the stored energy (J), charge (C), capacitance (F) and voltage (V). Express the energy per charge, or (in the case of capacitors) as V = (sqrt{2 E / C}). Introduce two compatible immediately calculate voltage and other related quantities using values (E.g., E and Q or E and C).
charge to voltage calculator
Energy (J) | Charge (C) | Capacitance (F) | Calculation | Voltage (V) |
---|---|---|---|---|
10.0 | 2.0 | — | V=E/Q=10/2 | 5.00 |
0.005 | — | 1e-6 | V=√(2E/C) | 100.0 |
0.02 | 0.01 | — | V=E/Q=0.02/0.01 | 2.00 |
5.0 | — | 1e-3 | V=√(2×5/1e-3) | 100.0 |
— | 0.5 | 2e-6 | V=Q/C=0.5/2e-6 | 250000.0 |
Frequently Asked Questions - energy charge voltage calculator:
How do I get voltage from energy and charge?
Use V = E / Q where E is joules and Q is coulombs.
How to get voltage to store energy in a capacitor?
Use V = sqrt(2E/C) where C is capacitance in farads.
What if I know Q and C?
Use V = Q / C.
How to compute stored energy from V and C?
Use E = 1/2 × C × V^2.
What units should I use?
Energy in joules (J), charge in coulombs (C), capacitance in farads (F), voltage in volts (V).
Can I use millifarads or microfarads?
Yes — convert units to farads first (µF → F = µF ×1e-6).
What if E or Q is zero?
If Q=0 voltage is undefined; if E=0 then V=0 for any finite Q or C.
Is this valid for batteries?
V=E/Q is a basic relation but batteries have internal resistance and inefficiencies to consider.
Why is capacitor voltage sqrt relation?
Because capacitor energy depends on V^2: E = 1/2 C V^2, so V ∝ sqrt(E/C).
Can I store large energy in small capacitors?
You need very high voltage; check capacitor voltage rating and safety limits.
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